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Ions in a certain volume of 0.20MNaCl(aq) are represented in the box above on the left. In the box above on the right, draw a particulate diagram that represents the ions in the same volume of 0.10MCaCl2

Ions in a certain volume of 020MNaClaq are represented in the box above on the left In the box above on the right draw a particulate diagram that represents the class=

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From the reference of the given NaCl, the 0.1 M  [tex]\rm CaCl_2[/tex] contains 4 Ca and 8 Cl ions.

From the given representation, the number of ions of Na and Cl in the 0.2 M NaCl is 8 Na ions and 8 Cl ions.

Since the 0.2 M solution contains 8 Na and 8 Cl.

The 0.1 M solution contains 4 Na and 4 Cl ions.

The molecule of [tex]\rm CaCl_2[/tex] has 1 Ca ion and 2 Cl ions.

The 0.1 M NaCl has 4 Na and 4 Cl.

0.1 M  [tex]\rm CaCl_2[/tex] will have 4 Ca and 8 Cl ions, as for each  Ca there are 2 Cl atoms.

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