Answer:
a) T=41.25 in-lb
b) Resulting stress=6493.5 lb/in^2
Explanation:
a) The torque is:
[tex]T=C*D*F[/tex]
where C is the torque coefficient, F the force and D is 3/8. Replacing:
[tex]T=0.22*3/8*500=41.25 in-lb[/tex]
b) The area is:
[tex]A=0.25\pi (D-\frac{0.9743}{n})^{2}=0.25\pi (3/8-\frac{0.9743}{16})^{2}=0.077 in^{2}[/tex]
The resulting stress is:
[tex]Resulting stress=\frac{F}{A}=\frac{500}{0.077} =6493.5 lb/in^{2}[/tex]
