Answer:
P( rolling 2 and head) =[tex]\frac{450}{10000}[/tex] .
Step-by-step explanation:
Given : Abdul used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables below.
To find : what is the probability of rolling a '2' on the number cube and the coin landing on heads up.
Solution : we have given :
Number 2 on cube rolled = 10 times
Total number of times it rolled = 100.
Probability = [tex]\frac{Favorable\ outcome}{Total\ outcome}[/tex].
Probability of 2 rolled on cube = [tex]\frac{10}{100}[/tex].
coin landing on heads up = 45.
Total number of times coin flip = 100.
Probability of landing on heads up = [tex]\frac{45}{100}[/tex].
Then, P( rolling 2 and head) = P( rolling 2) * P( head).
Both are independent
P( rolling 2 and head) =[tex]\frac{10}{100}[/tex] * [tex]\frac{45}{100}[/tex].
P( rolling 2 and head) =[tex]\frac{450}{10000}[/tex] .
Therefore, P( rolling 2 and head) =[tex]\frac{450}{10000}[/tex] .