Respuesta :
we are required in this problem to approximate tan α which α is less than 20 degrees.
In radians 20degrees is equal to 0.349; find tan 0.349=0.363
percentage error=(0.349-.363)*100/(0.363) =-3 percent error so for largest angle 20 degrees , the error is less than 10 percent
In radians 20degrees is equal to 0.349; find tan 0.349=0.363
percentage error=(0.349-.363)*100/(0.363) =-3 percent error so for largest angle 20 degrees , the error is less than 10 percent
Answer:
[tex]\alpha = 30.9 degree[/tex]
Explanation:
percentage error of approximation is less than 10%
so we will have
[tex]error = \frac{tan\alpha - \alpha}{tan\alpha} \times 100[/tex]
now we will have
[tex]10 = \frac{tan\alpha - \alpha}{tan\alpha} \times 100[/tex]
[tex]0.1 = \frac{tan\alpha - \alpha}{tan\alpha}[/tex]
now we have
[tex]0.1 tan\alpha = tan\alpha - \alpha[/tex]
[tex]0.9 tan\aplha = \alpha[/tex]
so here we have
[tex]\alpha = 30.9 degree[/tex]