Respuesta :
we can determine the vertex form of this equation by using the technique completing the squares
y = x^ 2 - 10x + 16
(k/2)^2 = (-10/2)^2 = 25
x^2 - 10x + 16 + 25 = y + 25
x^2 -10x + 25 = y + 25 - 16
(x - 5)^2 = y + 9
h is equal to 5 and k is equal to -9. 4a is equal to 1
y = x^ 2 - 10x + 16
(k/2)^2 = (-10/2)^2 = 25
x^2 - 10x + 16 + 25 = y + 25
x^2 -10x + 25 = y + 25 - 16
(x - 5)^2 = y + 9
h is equal to 5 and k is equal to -9. 4a is equal to 1