Respuesta :
The volume of the cylinder is calculated through the equation, V = πr²h. From the given, the ratio of the radii of Pipe A and Pipe B is 6:2 or 3:1. This is also the ratio of the heights of the Pipe. Therefore, the ratio of volume is,
V1 / V2 = π(3r)²3h / (πr²h) = 27 / 1
Thus, the ratio of the volumes is 27:1
V1 / V2 = π(3r)²3h / (πr²h) = 27 / 1
Thus, the ratio of the volumes is 27:1
The volume of the cylinder should be [tex]V = \pi r^2h[/tex]
And, the ratio of the volume should be 27:1.
Calculation of the volume:
Since Kent has two similar cylindrical pipes, Pipe A and Pipe B.
The radius of Pipe A is 6 cm, and the radius of Pipe B is 2 cm.
So, here the ratio should be like
[tex]= V1 \div V2 = \pi (3r)^2 3h \div (\pi r^2h) = 27 / 1[/tex]
Thus, the ratio of the volumes is 27:1
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