Respuesta :
y = mx + b
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
-3 = 12 + b
-3-12 = b
-15 = b
so ur equation is : y = -6x - 15
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
-3 = 12 + b
-3-12 = b
-15 = b
so ur equation is : y = -6x - 15
The equation of the line is y = -6x - 15
How to determine the equation?
The given parameters are:
Slope, m = -6
(x1, y1) = (-2, -3)
The equation is then calculated as:
y = m(x - x1) + y1
So, we have:
y = -6(x + 2) - 3
Expand
y = -6x - 12 - 3
Evaluate the like terms
y = -6x - 15
Hence, the equation of the line is y = -6x - 15
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