Answer : The mass of Fe and Cl in sample B is 3.341 g and 6.371 g respectively.
Explanation :
Law of definite proportion : It is defined as a given compound always contains exactly the same proportion of elements by weight.
The balanced chemical reaction will be,
[tex]2FeCl_3\rightarrow 2Fe+3Cl_2[/tex]
First we have to calculate the ratio of mass of [tex]FeCl_3[/tex].
[tex]\text{Ratio}=\frac{\text{Mass of }FeCl_3 \text{in sample A}}{\text{Mass of }FeCl_3 \text{in sample B}}[/tex]
[tex]\text{Ratio}=\frac{3.785g}{1.475g}=2.566[/tex]
Now we have to calculate the mass of Fe and Cl in sample B.
[tex]\text{Mass of Cl in sample B}=2.566\times \text{Mass of Cl in sample A}[/tex]
[tex]\text{Mass of Cl in sample B}=2.566\times 2.483g=6.371g[/tex]
and,
[tex]\text{Mass of Fe in sample B}=2.566\times \text{Mass of Fe in sample A}[/tex]
[tex]\text{Mass of Fe in sample B}=2.566\times 1.302g=3.341g[/tex]
Therefore, the mass of Fe and Cl in sample B is 3.341 g and 6.371 g respectively.
