Respuesta :
area=pir^2
d/2=r
8=d
8/2=4=r
aera=pi4^2
area=pi16
area=16pi in^2
C
frame 2 inches wide
add 2 to radius
2+4=6
A=pi6^2
A=pi36
A=36pi in^2
C
answer to both is C
d/2=r
8=d
8/2=4=r
aera=pi4^2
area=pi16
area=16pi in^2
C
frame 2 inches wide
add 2 to radius
2+4=6
A=pi6^2
A=pi36
A=36pi in^2
C
answer to both is C
The answer for the first question is C. 16π square inches
The area of a circle can calculated using the equation : A= πr2
Since the diameter = 8 in, the r= diameter/2
A= (4 in * 4 in)π
A= 16π square inches
The answer for the second question is C. 36π square inches
Since the frame is 2 in wide, it adds to the present 4 in radius.
The new radius = 6
A=(6 in *6 in)π
A= 36 π square inches
Thank you for posting your question. Please feel free to ask me more.
The area of a circle can calculated using the equation : A= πr2
Since the diameter = 8 in, the r= diameter/2
A= (4 in * 4 in)π
A= 16π square inches
The answer for the second question is C. 36π square inches
Since the frame is 2 in wide, it adds to the present 4 in radius.
The new radius = 6
A=(6 in *6 in)π
A= 36 π square inches
Thank you for posting your question. Please feel free to ask me more.