What is the perimeter of a triangle with vertices located at (-1, 4), (2, 7), and (1, 5), rounded to the nearest hundredth? A. 7.63 units B. 7.89 units C. 8.71 units D. 9.24 units

we are given with the points (-1,4), (2,7) and (1,5) as the sides of the triangle. The area of the triangle can be determined by determining first the length of the sides. Via distance formula, the sides are 3 sqrt 2, sqrt 5 and sqrt 5. The perimeter thus is equal to 8.71 units

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MrRoyal MrRoyal · Answer 2 · 2022-05-25T12:15:48+02:00

The perimeter of a triangle with vertices located at (-1, 4), (2, 7), and (1, 5) is 8.71 units

How to determine the perimeter?

The coordinates are given as:

(-1, 4), (2, 7), and (1, 5)

Calculate the distance between these points using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}[/tex]

So, we have:

[tex]AB = \sqrt{(-1 -2)^2 + (4 - 7)^2} = 4.24[/tex]

[tex]BC = \sqrt{(2-1)^2 + (7 - 5)^2} = 2.24[/tex]

[tex]AC = \sqrt{(-1-1)^2 + (4 - 5)^2} = 2.24[/tex]

The perimeter P is then calculated using:

P = 4.24 + 2.24 + 2.24

Evaluate the sum

P = 8.71

Hence, the perimeter of the triangle is 8.71 units