provate school in 2005
f(t)=85+18t
public school
g(t)=95+15t
graph
easy
replace g(t) and f(t) with y
y=18t+85
y=15t+95
input values for t and get values for y
y=18t+85
when t=0 y=85
when t=1 y=103
plot the oints (0,85) and (1,103)
y=15t+95
if t=0 then y=95
if t=1 then y=110
plot the points (0,95) and (1,110)
the easier way would just to be to solve the equatons but anyway
interscection point is (3 and 1/3,145)
so after 3 years (2008) it is about 145