The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 242 kJ/mol is required to break the chlorine–chlorine bond in Cl2. Determine the longest wavelength of radiation that possesses the energy to break the bond.

Respuesta :

The question ask to determine the longest wavelength of radiation that possesses the energy to break the bond and the minimum energy of 242kj/mol is required to break the chlorine-chlorine bond so the energy would be that the minimum wave length is 495nm and the high wavelength to it is the color green end of its wave

Answer:

The longest wavelength of radiation is 494.6 nm that will possess the energy to break the bond.

Explanation:

Energy required to break 1 mol of Cl-Cl bond = 242 kJ =242000 J

1kJ = 1000 J

1 mol = [tex]6.022\times 10^{23} [/tex] atoms/particles/ molecules

Energy required to break 1 of Cl-Cl bond = E

[tex]E=\frac{242000 J}{6.022\times 10^{23}}=4.0186\times 10^{-19} J[/tex]

Wave length of the radiation with energy E.

[tex]E=\frac{hc}{\lambda }[/tex]

h = Planck's constant

c = speed of the light

[tex]\lambda = \frac{6.626\times 10^{-34} J s\times 3\times 10^8 m/s}{4.0186\times 10^{-19} J}[/tex]

[tex]\lambda = 4.946\times 10^{-7} =494.6 nm[/tex]

The longest wavelength of radiation is 494.6 nm that will possess the energy to break the bond.