Respuesta :
Answer:
A. [tex]f(t)=4(t-1)^2+3[/tex]; the minimum height of the roller coaster is 3 meters from the ground.
Step-by-step explanation:
The given function is,
[tex]f(t) = 4t^2 - 8t + 7[/tex]
As the leading coefficient is 4 which is positive, so the parabola will open upward and at the vertex the value of the function will be minimum.
[tex]f(t)=4t^2-8t+7[/tex]
[tex]=4(t^2-2t)+7[/tex]
[tex]=4(t^2-2\cdot t\cdot 1+1^2-1^2)+7[/tex]
[tex]=4(t^2-2\cdot t\cdot 1+1^2-1)+7[/tex]
[tex]=4(t^2-2\cdot t\cdot 1+1^2)-4+7[/tex]
[tex]=4(t^2-2\cdot t\cdot 1+1^2)+3[/tex]
[tex]=4(t-1)^2+3[/tex]
So the vertex form will be,
[tex]f(t)=4(t-1)^2+3[/tex]
Hence the vertex will be at [tex](1,3)[/tex]
At vertex the value of the function ot f(t) is 3, so the minimum height of the roller coaster is 3 meters from the ground.

Answer:
Option A- [tex]f(t)=4(t-1)^2+3[/tex] ; the minimum height of the roller coaster is 3 meters from the ground.
Step-by-step explanation:
Given : The function [tex]f(t) = 4t^2-8t+7[/tex] shows the height from the ground f(t), in meters, of a roller coaster car at different times t.
To find : Write f(t) in the vertex form [tex]a(x - h)^2 + k[/tex], where a, h, and k are integers, and interpret the vertex of f(t).
Solution :
We have given the function [tex]f(t) = 4t^2-8t+7[/tex]
As the leading coefficient is 4 which is positive, so the parabola will open upward and at the vertex the value of the function will be minimum.
Now, we convert it into vertex form,
[tex]f(t)=4t^2-8t+7[/tex]
[tex]f(t)=4(t^2-2t)+7[/tex]
Making completing square,
[tex]f(t)=4(t^2-2t+1^2-1^2)+7[/tex]
[tex]f(t)=4(t^2-2t+1^2)-4+7[/tex]
[tex]f(t)=4(t-1)^2+3[/tex]
So the vertex form will be, [tex]f(t)=4(t-1)^2+3[/tex]
Where Vertex are (h,k)=(1,3) and a=4
At vertex the value of the function f(t) is 3.
So, the minimum height of the roller coaster is 3 meters from the ground.
Therefore, Option A is correct.