A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the tickets?
The question involved the concept of combination because the order of the friends being picked are not considered. There are a total of 8 friends and 5 out of them are picked. 8C5 = 56 Therefore, there are 56 ways.
