Look at this linear equation. 3x + 5y = 30 Which of the following equations can be used to solve for y in the linear equation above? y = - x + 30 y = 3x + 6 y = - x + 6 y = x + 30

Respuesta :

y=-
[tex] \frac{3}{5} x + 6[/tex]


Answer:

[tex]y=-\frac{3}{5}x+6[/tex]

Step-by-step explanation:

The given linear equation is

[tex]3x+5y=30[/tex]

We need to solve the above equation for y.

Using subtraction property of equality, subtract 3x from both sides.

[tex]3x+5y-3x=30-3x[/tex]

[tex]5y=30-3x[/tex]

Using division property of equality, divide both sides by 5.

[tex]y=\frac{30-3x}{5}[/tex]

[tex]y=\frac{30}{5}-\frac{3x}{5}[/tex]

[tex]y=6-\frac{3}{5}x[/tex]

Arrange the terms.

[tex]y=-\frac{3}{5}x+6[/tex]

Therefore, the required equation is [tex]y=-\frac{3}{5}x+6[/tex].