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Since it is stated that it is an ideal gas, we use the ideal gas equation to solve the volume of this gas sample. The ideal gas equation is expressed as:

PV = nRT
V = nRT / P
V = 0.200 (8.314) (400) / 200x10^3
V = 3.33 x 10^-3 m³ or 3.33L

Therefore, the correct answer is option B.
samueladesida43

The volume of a 0.200 mol of an ideal gas at 200 kPa and 400 K is 3.33L. Details about ideal gases can be found below.

How to calculate volume of an ideal gas?

The volume of an ideal gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

1.97 × V = 0.2 × 0.0821 × 400

1.97V = 6.57

V = 6.57 ÷ 1.97

V = 3.33L

Therefore, the volume of a 0.200 mol of an ideal gas at 200 kPa and 400 K is 3.33L.

Learn more about volume at: https://brainly.com/question/13338592

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