solve the triangle. round the lengths to the nearest tenth and angle measures to the nearest degree. a = 6, c = 11, b = 109°

Hello,

a=6,c=11,B=109°

b²=a²+c²-2accosB=6²+11²-2*6*11*cos 109°=199,9749963...
==>b=14,14125158...≈14.1
sin A/a=sin B/b==>sin A=6*sin 109°/14.14125...=0,4011746
==>A=23,6516...°≈24°
C=180°-109°-24°≈47°

Answer Link

ayoushivt ayoushivt · Answer 2 · 2022-07-14T15:08:14+02:00

The value of the sides of Triangle is 11 , 6 , 14.14 and the angles of the triangle are 109 , 23.65 , 47.35 degree.

What is a Triangle ?

A triangle is a polygon with three sides , three vertices and three angles.

The data is given for a Triangle

a = 6, c = 11, b = 109°

From the law of cosine

b² = c² + a² - 2ac cosB

b² = 11² + 6² - 2 * 6 * 11 * cos 109

b = 14.14

Using Law of Sine

a/ sin A = b/sin B =c /sin C

6 /sin A = 14.14 / sin 109

A = 23.65 degree

Similarly the value of C = 47.35 degree

Therefore the value of the sides of Triangle is 11 , 6 , 14.14 and the angles of the triangle are 109 , 23.65 , 47.35 degree.

To know more about Triangle

https://brainly.com/question/2773823

#SPJ2