The diagonal of a TV is 28 inches long. Assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact length and width of the TV? A. 14/2 inches by 14/2 inches B. 56 inches by 56/3 inches C. 14 inches by 14/3 inches D. 56/2 inches by 56/2 inches

Respuesta :

The shortest side of the 30-60-90 triangle is half of the length of the hypotenuse. The longer leg is sqrt 3 times the shorter leg. Given that the hypotenuse is 28 inches, the shorter leg is 14 inches. The longer leg is 14 sqrt 3 inches which is approximately equal to 24.25 inches. 

The  exact length and width of the TV is C. 14 inches by 14/3 inches.

Length and width

Given:

TV diagonal length= 28 inches

Diagonal pairs of right triangles=30-60-90

Hence:

Length

Sin30°=AB/28

0.5=AB/28

AB=14 inches

Width

Sin60°=BC/28

=√3/2=BC/28

BC=14√3 inches

Therefore the correct option is C.

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