Respuesta :
Amount in compound interest = p(1 + r/t)^nt where p is the initial
deposit, r = rate, t = number of compunding in a period and n = period.
Here, Amount after 6 months (0.5 year) = 1,950(1 + (4.25/100)/4)^(0.5 x 4) = 1,950(1 + 0.0425/4)^2 = 1,950(1 + 0.010625)^2 = 1,950(1.010625)^2 = 1,950(1.0213629) = $1,991.66
Compound interest = Amount - principal (initial deposit) = $1,991.66 - $1,950 = $41.66
Here, Amount after 6 months (0.5 year) = 1,950(1 + (4.25/100)/4)^(0.5 x 4) = 1,950(1 + 0.0425/4)^2 = 1,950(1 + 0.010625)^2 = 1,950(1.010625)^2 = 1,950(1.0213629) = $1,991.66
Compound interest = Amount - principal (initial deposit) = $1,991.66 - $1,950 = $41.66
Answer:
The amount in her account at the end of 6 months is $1991.58.
The compound interest is $41.58.
Step-by-step explanation:
The compound interest formula is given by:
[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]
Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.
In this exercise, we have:
[tex]A = 1950, n = 3, r = 0.0425[/tex]
What was the amount in her account at the end of 6 months:
This is a when t = 0.5 years.
So
[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]
[tex]A = 1950(1 + \frac{0.0425}{3})^{3*0.5} = 1991.58[/tex]
The amount in her account at the end of 6 months is $1991.58.
What is the compound interest?
The compound interest is the amount subtracted by the principal. So 1991.58-1950 = $41.58.