Jonathan finds a piece of metal that is 2 1/5 inches thick. He files off 3/10 inch. He adds a protective covering to the metal that is 2/10 inch thick. Then, he polishes the metal and removes an additional 1/10 inch. What is the final thickness of the metal?

Respuesta :

Answer:

The final thickness of the metal = 2 inches.

Step-by-step explanation:

Jonathan finds a piece of metal that is 2[tex]\frac{1}{5}[/tex]  inches thick.

The thickness of the metal = 2[tex]\frac{1}{5}[/tex] = [tex]\frac{11}{5}[/tex]

He files off [tex]\frac{3}{10}[/tex]  inch,

the thickness becomes =  [tex]\frac{11}{5}[/tex] - [tex]\frac{3}{10}[/tex] = [tex]\frac{19}{10}[/tex]

He adds a protective covering to the metal that is  [tex]\frac{2}{10}[/tex]  inch thick.

the thickness becomes,  [tex]\frac{19}{10}[/tex] + [tex]\frac{2}{10}[/tex] = [tex]\frac{21}{10}[/tex]

Then, he polishes the metal and removes an additional [tex]\frac{1}{10}[/tex] inch.

The final thickness becomes, [tex]\frac{21}{10}[/tex] - [tex]\frac{1}{10}[/tex]  = 2 inches