"two stations communicate via a 1-mbps satellite link with a propagation delay of 279 ms. the satellite serves merely to transmit data received from on station to another, with negligible switching delay. using hdlc frames of 1024 bits with 3-bit sequence numbers, what is the maximum possible data throughput, that is, what is the amount of data bits transferred using hdlc frame per second?"

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codiepienagoya codiepienagoya · Answer 1 · 2020-04-22T16:24:40+02:00

Answer:

The answer is "[tex]\bold{11964.9 \times 10^3 kbps}[/tex]"

Explanation:

The

[tex]t_{pd} = 279 \ ms[/tex]

[tex]t_{single} = \frac{Bits \ HDLC} {Link \ rate}\\[/tex]

[tex]t_{single} = \frac{1024 }{10^6} \ ms\\[/tex]

Transmit station can controls at most 7 frames in 3 bit sequence and without act total time to transmit.

Total time (t) = time for first frame + 2(frame delays)

[tex]t=\frac{1024}{10^6}+ 279+279\\\\t= 0.571 m[/tex]

during the time t frame sent = 7 So, data on each frame is

frame = frame size - ( flag + address+control+fcs bits +flag hits)

frame = 1024 -(8+8+8+16+8)

frame= 976 bits frame

through put = [tex]\frac{7 \times 976}{0.571 \times 10^{-3}}\\[/tex]

through put = [tex]\frac{6832 \times 1000}{0.571}[/tex] = [tex]11964.9 \times 10^3[/tex] kbps