Answer:
Step-by-step explanation:
The shape of bathysphere submarine is a sphere and can be imagined as concentric sphere.
Given inside diameter of bathysphere = 56in or radius will be [tex]\frac{56}{2}[/tex] inch
Volume of inside sphere = [tex]\frac{4}{3} \pi r^{3}[/tex] = [tex]\frac{4}{3}\pi 28^{3}[/tex]
Since the steel is 1.5 inch thick, the volume of outside sphere = Â [tex]\frac{4}{3} \pi r^{3}[/tex]
The changed r will  [tex]\frac{4}{3} \pi r^{3}[/tex] = [tex]\frac{4}{3}\pi \frac{57.5}{2}^{3}[/tex]
Volume of steel = [tex]\frac{4}{3}\pi 28.75^{3} -\frac{4}{3}\pi 28^{3}[/tex] = [tex]\frac{4}{3}\pi (28.75^{3} -28^{3})[/tex]
