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A circular bar will be subjected to an axial force (P) of 2000 lbf. The bar will be made of material that has a strength (S) of 24 kpsi. After some calculation, the designer has selected a standard 1/2 in diameter (d) bar. The factor of safety (n) is ____. Round the answers to three significant digits.

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Answer:

[tex]n = 2.36[/tex]

Explanation:

The stress experimented by the circular bar is:

[tex]\sigma = \left[\frac{2000\, lbf}{\frac{\pi}{4}\cdot (0.5\,in)^{2}}\right]\cdot \left(\frac{1\,kpsi}{1000\,psi} \right)[/tex]

[tex]\sigma = 10.186\,kpsi[/tex]

The safety factor is:

[tex]n = \frac{24\,kpsi}{10.186\,kpsi}[/tex]

[tex]n = 2.36[/tex]

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