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A load of 35 N attached to a spring hanging
vertically stretches the spring 8.1 cm. The
spring is now placed horizontally on a table
and stretched 12 cm.
What force is required to stretch it by this
amount?
Answer in units of N

Respuesta :

amareshshukla

Answer:

51.85 N

Explanation:

when hanging vertically,

mg = k*x  so we get k = mg/x = 35/8.1  N/cm

now for x = 12cm, we have to calculate F,

so F = k*x =  35/8.1 * 12 = 51.85 N

raphealnwobi

The force required to stretch the spring 12 cm is 51.85 N

Hooke's law states that the force applied to a spring is directly proportional to its displacement. It is given by:

F = kx;

where F is the force, k is the spring constant and x is the displacement.

A load of 35 N attached to a spring hanging  vertically stretches the spring 8.1 cm. Hence:

35 = 8.1k

k = 4.32 N/cm

For a displacement of 12 cm:

F = 4.32 N/cm * 12 cm = 51.85 N

The force required to stretch the spring 12 cm is 51.85 N

Find out more at: https://brainly.com/question/14670501

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