Answer:
[tex] 2 {x}^{2} + 6x + 13 = 0[/tex]
Step-by-step explanation:
[tex] - 4 {x}^{2} - 13 - 2x = 4x - 2 {x}^{2} \\ 4x - 2 {x}^{2} + 4 {x}^{2} + 13 + 2x = 0 \\ 4 {x}^{2} - 2 {x}^{2} + 4x + 2x + 13 = 0 \\ \purple{ \boxed{ \bold{2 {x}^{2} + 6x + 13 = 0}}} \\ is \: the \: standard \: form \: [/tex]
