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# 13. The sum of the squares of three consecutive positive integers is 770. What is the largest
of these integers?
(A) 15
(B) 16
(C) 17
(D) 18
(E) 19​

Respuesta :

Mibo

Step-by-step explanation:

The three consecutive numbers are 15 16 and 17 because when you find out the squares 15 = 225 16 = 256 17 = 289

Now add these numbers 225 + 256 +289 = 770

So the largest is 17 C option

abidemiokin

The largest  of these integers is 17T

Let the 3 consecutive positive integers be x-1, x and x + 1

If the sum of the squares of three consecutive positive integers is 77, then;

  • (x-1)² + x² + (x+1)² = 77

Expand

x²-2x+1 + x²+x²+2x+1 = 770

3x²+2 = 770

3x² = 750

x² = 250

x = 16

Largest number = 16 + 1 = 17

Hence the largest  of these integers is 17

Learn more on expression here: https://brainly.com/question/25968875

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