I NEED HELP PLEASE ASAP !

The first rule you need to know is
[tex](a^b)^c=a^{bc}[/tex]
So, you have
[tex]\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}[/tex]
The second rule you need to know is
[tex]\dfrac{a^b}{a^c}=a^{b-c}[/tex]
So, you have
[tex]\dfrac{x^{-150}}{x^{-144}}=x^{-150-(-144)}=x^{-150+144}=x^{-6}[/tex]
Answer:
- 6
Step-by-step explanation:
(x²⁵)⁻⁶/(x⁻³)⁴⁸ =
= (x²⁵ˣ⁻⁶)/(x⁻³ˣ⁴⁸)
= (x ⁻¹⁵⁰)/(x ⁻¹⁴⁴)
= x ⁻¹⁵⁰ ⁻⁽⁻¹⁴⁴⁾
= x ⁻¹⁵⁰⁺¹⁴⁴
= x ⁻⁶