Respuesta :
Answer:
The charge flows through a point in the circuit during the change is 0.044 C.
Explanation:
Given that,
Number of turns in the copper wire, N = 200
Area of cross section, [tex]A=1.2\times 10^{-3}\ m^2[/tex]
Resistance of the circuit, R = 118 ohms
If an externally applied uniform longitudinal magnetic filed in the core changes from 1.65 T in one direction to 1.65 T in the opposite direction.
We need to find the charge flows through a point in the circuit during the change. Due to change in magnetic field an emf is induced in it. It is given by :
[tex]\epsilon=\dfrac{d\phi}{dt}[/tex]
Using Ohm's law :
[tex]\epsilon=IR[/tex]
[tex]IR=-\dfrac{d\phi}{dt}\\\\I=-\dfrac{1}{R}\dfrac{d\phi}{dt}[/tex]
Electric current is equal to the rate of change of electric charge. So,
[tex]dq=\dfrac{NA(B(0)-B(t))}{R}\\\\dq=\dfrac{200\times 1.2\times 10^{-3}(1.65+1.65)}{18}\\\\dq=0.044\ C[/tex]
So, the charge flows through a point in the circuit during the change is 0.044 C.
