During the first 15 weeks of the 2016 season of a certain professional football​ league, the home team won 141 of the 241 ​regular-season games. Is there strong evidence of a home field advantage in this​ league? Test an appropriate hypothesis and state your conclusion. Be sure the appropriate assumptions and conditions are satisfied before proceeding with the hypothesis test.

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Answer:

The answer is 2.0190

Step-by-step explanation:

From the given question,

We recall that,

p = 141/241 = 0.5850

so, p = 0.5

The Hypothesis is:

H₀ : P = 0.5, this means that  H0:50% of the games played will be won

vs

H₁ : P > 0.5, This indicates that, win is greater than 0.5 due to home field advantages.

n=241,x=141

Then,

SD(p)=√(p*q/n)=√(0.5*0.5/141)=0.0421

z = p - p/ SD (p) = 0.5850 - 0.5/0.0421 = 0.085/0.0421 =2.0190

therefore, there is strong evidence that there is home field advantages in professional football.

Following are the calculation to the hypothesis test:

[tex]\to \hat{p}= \frac{141}{241}=0.5850 \\\\\to p=0.5[/tex]

Hypothesis:

[tex]H_{0}:P=0.5[/tex] implies [tex]H_0:50\%[/tex] of a games would be won.

vs

[tex]H_{1}:P>0.5[/tex] because of home-field advantages, the victory exceeds  [tex]0.5[/tex] . [tex]\to n=241 \\\\\to x=141\\\\\to SD(p)=\sqrt{(\frac{p\times q}{n})}=\sqrt{(\frac{0.5\times 0.5}{241})}=\sqrt{(\frac{0.25}{241})}= \sqrt{0.001}=0.0322 \\\\\to z=\frac{\hat{p}-p}{SD(p))}=\frac{0.5850-0.5}{0.0322}=\frac{0.085}{0.0322}=1.624\\\\ \to P(Z>1.624)=0.0521879[/tex]

conclusion [tex]P-value =0.0521879<0.05[/tex], As a result, we reject the null hypothesis, i.e. there's really significant evidence that home-field advantage exists in pro football.

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