Answer:
Age of the tool = 15411.75 years
Explanation:
Assume half life of 14C = 5730 years
Calculate rate constant using formula:
[tex]t_{1/2} = \frac{ln 2}{k}[/tex] thus [tex]k = \frac{ln 2}{t_{1/2}} = 1.21E-4[/tex]
Assuming initial concentration, Co of 14C = 100%
Final concentration, C of 14C = 15.5%
Use formula:
[tex]ln \frac{C}{Co} = kt[/tex]
thus
[tex]ln \frac{100}{15.5} = (1.21E-04) ( t )[/tex]
t = 15411.75 years
Answer:
1377.8years
Explanation:
Using
0.693/t1/2 = 2.303/t log Ao/A
Where t1/2= half life
t= time or age of the bone
Ao= amount of radioactive material at time t=0
A= amount of radioactive material at time t
0.693/5670 = 2.303/t log Ao/Ao-0.155Ao
0.693/5670= 2.303/t log Ao/0.845Ao
0.693/5670= 2.303/t log 1/0.845
0.693/5670= 0.1684/t
t= 1377.8years
