Answer:
[tex]s=-4.905*t^{2} +20*t+120[/tex]
The equation corresponds to a quadratic function.
Step-by-step explanation:
Given
[tex]s=-\frac{1}{2} gt^{2} +v_{0} t+s_{0}[/tex]
where
[tex]g=9.81\frac{m}{s^{2} }\\ v_{0}=20\frac{ft}{s} \\ s_{0} =120 ft[/tex]
the function that describes the height of Joan’s basketball is
[tex]s=-\frac{1}{2} (9.81\frac{m}{s^{2} })t^{2} +20\frac{ft}{s}*t+120 ft\\ s=-4.905*t^{2} +20*t+120[/tex]
The equation corresponds to a quadratic function.