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Group 1 cations precipitate easily in a relatively high concentration of hydrochloric acid. After the separation from the other group 1 cations, the presence of lead can be tested by addition of potassium chromate. Explain what is wrong with the given equation for this test. Pb(aq) + CrO4(aq) <-> PbCrO(aq)

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Answer:

The oxidation of the lead is not indicated, also the charge on Chromate,

Explanation:

The lead in the aqueous form is +2 and the charge of Chromate is -2 i.e CrO4^-2, and also the product should be PbCrO4

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