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If you were to separate all of the electrons and protons in 1.00 g (0.001 kg) of matter, you’d have about 96,000 C of positive charge and the same amount of negative charge. If you placed these charges 8.00 m apart, how strong would the attractive forces between them be?

Respuesta :

Answer:

The attractive force between them is [tex]1.296 \times 10^{18}[/tex] N

Explanation:

Given:

Charge [tex]q = 96000[/tex] C

Distance between two charges [tex]r = 8[/tex] m

According to the coulomb's law,

    [tex]F = \frac{kq^{2} }{r^{2} }[/tex]

Where [tex]k = 9 \times 10^{9}[/tex] = force constant.

   [tex]F = \frac{9 \times 10^{9} \times (96000)^{2} }{8^{2} }[/tex]

   [tex]F = 1.296 \times 10^{18}[/tex] N

Therefore, the attractive force between them is [tex]1.296 \times 10^{18}[/tex] N

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