During the experiment, you adjusted the length of the rheostat LL6 so that 1 glow flowed through bulb H. Now that we have seen that the (conduction) current measured by a DMM corresponds to the same physical concept as ‘glow’, it makes sense to ask "what current goes through bulb H when 1 glow goes through bulb H?" The consensus in the past has been about 30 mA but you might have been using a slightly larger or smaller current. Remember that you assumed that the bulbs in circuit 7 were identical. If the resistance of rheostat LL6 has been adjusted so that 30 mA flows through bulb H then what current flows through bulb B? What current flows through bulb C?

Respuesta :

Answer:

IB = IC =IH = 30 mA

Explanation:

please look at the solution in the attached Word file

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The current flows through bulb B and bulb C will be 30 mA.The value of current in the both bulb is same.

What is electric current?

The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.

The given data in the problem is;

Resistance in the bulb H,B,C =R

Voltage in the bulb H,B,C =V

The points H, B, and C are in parallel

From ohm's law;

The electric current is the ratio of voltage and resistance;

[tex]\rm I=\frac{V}{R} =30 \ mA[/tex]

Resistance is constant due to which the current is directly propotional to the voltage.The points H, B, and C are in parallel due to which Voltage in the bulb H,B,C =V.

So the value of the electric current is same.

[tex]\rm I_H = I_B=I_C = 30 mA[/tex]

Hence the current flows through bulb B and bulb C will be 30 mA.

To learn more about the electric current refer to the link;

brainly.com/question/7643273