Respuesta :
Answer: They must hire 12 Counselors and 18 Aides
Step-by-step explanation: The most important factor here is the fact that they need to minimize hiring costs. The math camp can afford to hire up to 45 members of staff and can as well run properly with 30 members of staff.
The camp must have at least 10 aides (simply put, any number above 10 will do). Also they may have up to 3 aides for every 2 counselors, that is the ratio of counselor to aide has been given as;
2 : 3
If the math camp decides to hire the minimum required in order to minimize cost, they would be hiring 30, and that would be divided according to the following ratio;
(Counselor):
30 x 2/5 = 12
(Aide):
30 x 3/5 = 18
Hence they would be hiring 12 counselors at a cost of
2400 x 12 = 28800
And 18 Aides at a cost of
1100 x 18 = 19800
Therefore the total (minimum) cost of hiring staff is $48,600
Using the minimum number of staff required for the camp to run properly, the number of aides and counsellors required to minimize cost is 18 and 12 respectively.
At minimum cost :
- Total number of staffs to hire = 30
3 aides for every 2 counsellors gives a ratio of 3 : 2
Number of aides and counsellors to hire :
Aides = (3/5) Ă— 30 = 18
Counsellors = 30 - 18 = 12
Therefore, to minimize cost, the number of aides and counsellors the camp may hire ls 18 and 12 respectively.
Learn more : https://brainly.com/question/18796573