Answer:
The average angular acceleration is [tex]\alpha =125.487 rad /s^2[/tex]
Explanation:
From the question we are told that
From the question we are told that
The length of the bat is [tex]l = 0.85m[/tex] \
The initial linear velocity is [tex]u = 0 m/s[/tex]
The time is [tex]t = 0.15s[/tex]
The velocity at t is [tex]v = 16 m/s[/tex]
Generally average angular acceleration is mathematically represented as
[tex]\alpha = \frac{w_f - w_o}{t}[/tex]
Where [tex]w_f[/tex] is the finial angular velocity which is mathematically evaluated as
[tex]w_f = \frac{v}{l}[/tex]
[tex]w_f = \frac{16}{0.85}[/tex]
[tex]= 18.823 rad/s[/tex]
and [tex]w_o[/tex] is the initial angular velocity which is zero since initial linear velocity is zero
So
[tex]\alpha = \frac{18.823 - 0}{0.15}[/tex]
[tex]\alpha =125.487 rad /s^2[/tex]
