Answer:
[tex]P(B \cup b) =\frac{4}{7}[/tex]
Step-by-step explanation:
Total Number of students, the Universal Set [tex]n(\mathcal{E})[/tex]=28
Let the number of those who play basketball =B
Let the number of those who play baseball =n
Number who play neither sport, [tex]n(B\cup b)'[/tex]=12
From Set Theory,
Since we want to determine the probability that a student chosen randomly from the class plays basketball or baseball, we only simply exclude those who play neither sports.
Mathematically,From Set Theory,
[tex]\mathcal{E}=n(B \cup b)+n(B \cup b)'\\28=n(B \cup b)+12\\n(B \cup b)=28-12\\n(B \cup b)=16[/tex]
The Probability that a student chosen randomly from the class plays basketball or baseball
[tex]P(B \cup b)=\frac{n(B \cup b)}{n(\mathcal{E})}\\=\dfrac{16}{28}\\ =\dfrac{4}{7}[/tex]
