Answer:
(0.0657,0.0943) is the 90% confidence interval for the population proportion of visitors that click on the advertisement.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 978
Percentage of users that clicked on advertisement = 8%
Sample proportion:
[tex]\hat{p} = 0.08[/tex]
90% Confidence interval:
[tex]\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
[tex]z_{critical}\text{ at}~\alpha_{0.10} = 1.645[/tex]
Putting the values, we get:
[tex]0.08\pm 1.645(\sqrt{\dfrac{0.08(1-0.08)}{978}})\\\\= 0.08\pm 0.0142\\\\=(0.0658,0.0942) = (6.57\%,9.43\%)[/tex]
(0.0657,0.0943) is the 90% confidence interval for the population proportion of visitors that click on the advertisement.