The probability of winning the shell games if you randomly pick is 1 in 3. What would be the approximate probability of winning 4 games in a row?

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Answer:

1 /81

Step-by-step explanation:

1/3 * 1/3 * 1/3 * 1/3 (One for each game) = 1/81

This question is based on the probability. Therefore, the approximate probability of winning 4 games in a row is [tex]\dfrac{1}{81}[/tex].

Given:

The probability of winning the shell games if you randomly pick is 1 in 3.

We need to calculate the approximate probability of winning 4 games in a row.

According to the question,

By using the formula of probability,

[tex]Probability = \dfrac{Number \, of \, favourable \, outcome}{Total \, number \,of\, Outcome}[/tex]

It is given that,  probability of winning is 1 in 3.

Now, calculating the approximate probability of winning 4 games in a row is,

[tex]\dfrac{1}{3} \times\dfrac{1}{3} \times \dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{81}[/tex]

Therefore, the approximate probability of winning 4 games in a row is [tex]\dfrac{1}{81}[/tex].

For more details, prefer this link:

https://brainly.com/question/11234923