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A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet after t seconds is given by the function h equals negative 16 t squared plus 46 t plus 6. After how many seconds will the ball hit the ground? A. 3 B. 4 C. 5 D. 6

Respuesta :

leecapman

Answer:

t = 3 seconds

Step-by-step explanation:

This is a quadratic equation. First set it up and set it equal to 0 (the ground).

-16t² + 46t + 6 = 0

The quadratic formula is (-b ± √(b² - 4ac))/2a

a= -16

b = 46

c = 6

Plug those numbers into the equation and solve which will result in -.125 or 3.

The time of course can not be negative in this case. Therefore, t=3 seconds.

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