Answer:
0.0879 is the probability that out of 5 randomly selected consumers, three are comfortable with delivery by drones.
Step-by-step explanation:
We are given the following information:
We treat drone deliveries as a success.
P(consumers comfortable having drones deliver) = 25% = 0.25
Then the number of consumers follows a binomial distribution, where
[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]
where n is the total number of observations, x is the number of success, p is the probability of success.
We have to evaluate:
P(Exactly 3 customers out of 5 are comfortable with delivery by drones)
Here,
[tex]n = 5\\x = 3\\p = 0.25\\q = 1 - p = 1-0.25=0.75[/tex]
Putting values, we get,
[tex]P(x =3)\\\\= \binom{5}{3}(0.25)^3(1-0.25)^2\\\\= 0.0879[/tex]
0.0879 is the probability that out of 5 randomly selected consumers, three are comfortable with delivery by drones.
