Answer:
a) Miss
b) The cache content is therefore stored in the location point 6
Explanation:
Consider the data:
Total number of words in the block = 16
Number of word blocks = 1
Therefore, each block size = [tex]\frac{Total number of words in the block}{Number of word blocks}[/tex]
= [tex]\frac{16 words}{1 word block}[/tex]
= 16 words per block
a) Consider the address 54
The remainder of the cache represents the cache's address.
Therefore, the remainder of 54%16 = 6. The cache content is therefore stored in the location point 6 and it is considered as a miss.
The word address 54 is a Miss
The cache content at this point is stored in location point 6
This refers to the term used in computer architecture which means that certain addresses in the memory of the computer can have unique identification with certain bytes of memory.
Total number of words in the block = 16
Number of word blocks = 1
To calculate the block size = Total no of words in the block/Number of word blocks.
= 16-word blocks
Hence, if we look at address 54, we can note that according to system architecture, the remaining cache is used to represent the address of the cache.
Therefore, 54%16 = 6.
This means that the cached content is stored in location point 6 and it is considered a miss because the cache is not available in the cache memory which then prompts the CPU to fetch the requested data from the main memory.
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