Given:
The length of a basketball court is twice its width.
The perimeter of the perimeter is 150 feet.
To find the length and width of the basketball court.
Formula
The perimeter of the rectangle is
[tex]P = 2(l+b)[/tex]
where, l be the length of the rectangle and
b be the width of the rectangle.
Now,
As per the problem,
Let, the width be [tex]x[/tex], so the length be [tex]2x[/tex]
So,
The perimeter is = [tex]2(x+2x) = 6x[/tex]
According to the problem,
[tex]6x = 150\\or, x = \frac{150}{6}[/tex]
[tex]or, x = 25[/tex]
Therefore,
the width of the court is 25 ft and length = 2×25 = 50 ft
Hence,
The length and width of the basketball court is 50 ft and 25 ft respectively.
