You drop a ball from a stair case that is 36 ft high. By the time you get down the stairs to measure the height of the bounce, the ball has bounced four times and has a height of 2.25 ft after its fourth bounce. How high did the ball bounce after it first hit the floor?

Respuesta :

Answer:

18 feet

Step-by-step explanation:

After each bounce, the ball reaches only a percentage of the maximum height it reached before.

The first height is 36 feet, after the first bounce, it will be 36*r, where r is the ratio of the height the ball can still reach by the previous maximum height.

In the second bounce, the height is 36*r^2

In the third bounce, the height is 36*r^3

In the fourth bounce, the height is 36*r^4, and this value is 2.25 ft, so:

36*r^4 = 2.25

r^4 = 2.25/36

r^4 = ┬а0.0625

r = 0.5

So, after the first bounce, the height is:

36*r = 36*0.5 = 18 feet

The height should be 18 feet.

Given that,

  • You drop a ball from a stair case that is 36 ft high.
  • By the time you get down the stairs to measure the height of the bounce, the ball has bounced four times and has a height of 2.25 ft after its fourth bounce.

Based on the above information, the calculation is as follows:

The first height is 36 feet.

Now after the first bounce, it will be 36r

Here r is the ratio of the height

In the second bounce, the height is [tex]36\times r^2[/tex]

In the third bounce, the height is [tex]36\times r^3[/tex]

In the fourth bounce, the height is [tex]36\times r^4[/tex], and this value is 2.25 ft, so:

Now

[tex]36\times r^4 = 2.25\\\\r^4 = 2.25\div 36\\\\r^4 = 0.0625[/tex]

r = 0.5

Now ┬а

So, after the first bounce, the height is:

= 36r

= 36(0.5)

= 18 feet

Therefore we can conclude that The height should be 18 feet.

Learn more: brainly.com/question/17429689

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