Answer:
The second kinetic energy is 162 J.
Explanation:
Given that,
Mass, [tex]m_1=15\ g[/tex]
Velocity, [tex]v_1=7\ cm/s[/tex]
Kinetic energy, [tex]K_1=147\ ergs[/tex]
Mass, [tex]m_2=10\ g[/tex]
Velocity, [tex]v_2=9\ cm/s[/tex]
We need to find kinetic energy [tex]K_2[/tex]. Kinetic energy is given by :
[tex]K=\dfrac{1}{2}mv^2[/tex]
So,
[tex]\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J[/tex]
So, the second kinetic energy is 162 J.
