The centripetal acceleration might better be expressed as −ω2r⃗ (t)−ω2r→(t) because it is a vector. The magnitude of the centripetal acceleration is v2radial/Rvradial2/R. The magnitude of the centripetal acceleration is v2tangential/Rvtangential2/R. A particle that is going along a path with local radius of curvature RRR at speed sss experiences a centripetal acceleration −s2/R−s2/R. If you are in a car turning left, the force you feel pushing you to the right is the force that causes the centripetal acceleration. In these statements vradialvradialv_radial refers to the component of the velocity of an object in the direction toward or away from the origin of the coordinate system or the rotation axis. Conversely, vtangentialvtangentialv_tangential refers to the component of the velocity perpendicular to vradialvradialv_radial. Identify the statement or statements that are false.

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moya1316 moya1316 · Answer 1 · 2020-04-24T08:14:14+02:00

Answer:

false b) a = v²(radial) / r and e)

Explanation:

Let's review given statement separately

a) centripetal acceleration

a = v² / r

linear and angular velocity are related

v = w r

we substitute

a = w²r

this acceleration is directed to the center of the circle, so the vector must be negative

a = - w r2

the bold are vector

True this statement

b) the magnitude is the scalar value

a = v² / r

where v is the tangential velocity, not the radial velocity, so this statement is

False

c) This is true

a = v²/ r

this speed is tangential

d) Newton's second law is

F = m a

if the acceleration is centripetal

F = m (- v² / r)

we substitute

F = m (- s² / R)

the statement is true

e) when the car turns to the left, the objects have to follow in a straight line, which is why

you need a force toward the center of the circle to take the curve.

Consequently there is no outward force

This statement is false