The equation represents the combustion of sucrose. C12H22O11 + 12O2 Right arrow. 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? 0.029 mol 0.250 mol 0.351 mol 3.00 mol

Respuesta :

Answer: 0.029 mol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

The balanced chemical equation is:

[tex]C_{12}H_{22}O_{11}+12O_2\rightarrow 12CO_2+11H_2O[/tex]

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{10.0g}{342g/mol}}=0.029moles[/tex]

Thus there are 0.029 moles of sucrose

Answer:

A

Explanation: