Find BC, Round to the nearest tenth

Given:
Given that the measure of ∠A is 74°
The length of side b is b = 6.
The length of side c is c = 5.
The length of side BC is a.
We need to determine the value of BC.
Value of BC:
The value of BC can be determined using the law of cosine formula.
Thus, we have;
[tex]a^2=b^2+c^2-2bc \ cos (A)[/tex]
Substituting b = 6, c = 5 and ∠A = 74°, we get;
[tex]a^2=6^2+5^2-2(6)(5) \ cos \ 74^{\circ}[/tex]
[tex]a^2=36+25-2(30)(0.28)[/tex]
[tex]a^2=36+25-16.8[/tex]
[tex]a^2=44.2[/tex]
[tex]a=6.6[/tex]
Thus, the length of BC is 6.6 units.