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Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alphabet, A through D. The values in the partially completed grid are measured cell potentials for a cell consisting of electrode #1 and electrode #2. You may assume that each galvanic cell was properly constructed with the appropriate metals and solutions and that all the measured values in the grid are accurate.

electrode #1 ?

C

B

D

A

electrode #2?

Ecell(volts)

Ecell(volts)

Ecell(volts)

Ecell(volts)

C

0

0.91

0.62

0.26

B

0.91

0

1.53

D

0.62

1.53

0

0.36

0 volts

0.10 volts

0.26 volts

0.36 volts

0.55 volts

0.62 volts

0.65 volts

0.88 volts

0.98 volts

1.17 volts

1.27 volts

1.79 volts

1.89 volts

Respuesta :

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  [tex]E_{cell}__{AC}} = 0.94[/tex]

Explanation:

  From the question we are told that

          the cell voltage for AD is  [tex]E_{cell}__{AD}} = 1.56V[/tex]

From the data give we can see that

               [tex]E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}[/tex]

i.e           [tex]1.56 - 1.53 = 0.03[/tex]

   In the same way we can say that

              [tex]E_{cell}__{AD}}-E_{cell}__{CD}} = E_{cell}__{AC}}[/tex]

=>        [tex]E_{cell}__{AC}}=1.56- 0.62[/tex]

                       [tex]E_{cell}__{AC}} = 0.94[/tex]

       

             

Ver imagen okpalawalter8

Galvanic cells are the voltaic cells that generate an electric current from redox reactions. The cell potential of cells A and C will be 0.94 volts.

What are the cell potentials?  

The cell potential is the estimation of the gained or lost electrons by the species on the electrode of the electrochemical cell.

Given, the cell voltage for cells A and D is 1.56 V.

Cell potential between A and B cells is calculated as:

[tex]\begin{aligned} \rm E_{cell}_{(AB)} &= \rm E_{cell}_{(AD)} - \rm E_{cell}_{(BD)}\\\\&= 1.56 - 1.53\\\\&= 0.03 \end{aligned}[/tex]

Similarly, cell potential between A and C cells is calculated as:

[tex]\begin{aligned} \rm E_{cell}_{(AC)} &= \rm E_{cell}_{(AD)} - \rm E_{cell}_{(CD)}\\\\&= 1.56 - 0.62\\\\&= 0.94 \end{aligned}[/tex]

Therefore, the cell potential between A and C cell is 0.94 volts.

Learn more about galvanic cells here:

https://brainly.com/question/17238183