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A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fracture, given that: the applied load is 5560 N the flexural strength is 105 MPa the separation between the supports is 45 mm Input your answer as X.XX mm, but without the unit of mm.

Respuesta :

Answer:

radius = 9.1 × [tex]10^{-3}[/tex] m

Explanation:

given data

applied load = 5560 N

flexural strength = 105 MPa

separation between the support =  45 mm

solution

we apply here minimum radius formula that is

radius = [tex]\sqrt[3]{\frac{FL}{\sigma \pi}}[/tex]      .................1

here F is applied load and  is length

put here value and we get

radius =  [tex]\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}[/tex]  

solve it we get

radius = 9.1 × [tex]10^{-3}[/tex] m

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